What is the energy in electron-volts (eV) of a photon of green light that has a wavelength of 520 nm? (1.0 m = 1.0 × 10^-9m)


3.8 × 10^-19eV

3.4 × 10^-40eV

2.4eV

2.2 × 10^-21eV

Verified Answer :

Answer:

The energy of a photon is \(3.8\times10^{-19}\ eV\).

Explanation:

Given that,

Wave length = 520 nm

\(1 nm = 1\times 10^{-9}\ m\)

Using plank's equation

\(E =h u\)...(I)

Here, h = plank constant

υ = frequency

Now, using wave equation

\(c =\lambda\times u\)

The equation can be written as:

\(u = \dfrac{c}{\lambda}\)

Here, c = speed of light

λ= wave length of light

Put the value of υ in equation (I)

The energy of photon is

\(E = h\times\dfrac{c}{\lambda}\)

\(E = \dfrac{6.63\times10^{-34}\times3\times10^{8}}{520\times10^{-9}}\)

\(E=3.8\times10^{-19}\ eV\)

Hence, The energy of a photon is \(3.8\times10^{-19}\ eV\).