Cylinders A and B are similar solids. The base of cylinder A has a circumference of 4π units. The base of cylinder B has an area of 9π units.


The dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B?




Verified Answer :

the base of cylinder b has an are of 9 unites

Answer:

The factor is \(\frac{3}{2}\).

Step-by-step explanation:

Given : Cylinders A and B are similar solids.

The base of cylinder A has a circumference of  \(4\pi\) units.

The base of cylinder B has an area of  \(9\pi\) units.

To find :  The dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B?

Solution :

Let x be the factor.

So, according to question,

\(\text{Dimension of cylinder A}\times x = \text{Dimension of cylinder B}\)   ........[1]

The dimension refer here are radius of both cylinders.

In cylinder A,

Circumference of base is \(4\pi\) units.

Circumference of base of cylinder is \(C=2\pi r\)

\(4\pi=2\pi r\)

\(r=2\)

The dimension of cylinder A is r=2

In cylinder B,

Area of cylinder is \(9\pi\) units.

Area of base of cylinder is \(A=\pi r^2\)

\(9 \pi=\pi r^2\)

\(r^2=9\)

\(r=3\)

The dimension of cylinder B is r=3

Substitute in [1]

\(2x=3\)

\(x=\frac{3}{2}\)

Therefore, The factor is \(\frac{3}{2}\).