So \(2^{ \frac{5}{2} }\) is the same as \(\sqrt{ 2^{5} }\) and therefore \(2^{ \frac{3}{2} }\) is \(\sqrt{ 2^{3} }\).
So.. the \(\sqrt{32}\) minus \(\sqrt{8}\).
We can pull a 4 out of the 32 to make 4\(\sqrt{2}\) as 16 times 2 is 32
We can pull a 2 out of the 8 to make 2\(\sqrt{2}\).
Now they have like bases, so to speak, and 4-2 is 2.
So the answer is 2\(\sqrt{2}\).
