The lengths of the parallel sides of a trapezoid are represented by a and b and it's height by h. The area of the trapezoid can be written as 1/2 ah+1/2 bh. Express this area as the product of two factors.
A=1/2ab+1/2bh
each term has 1/2b in common therefor it can be factored out
1/2b(a+b)
The area of the trapezoid as the product of two factors is \(\frac{1}{2} h(a+b)\) .
A trapezoid is a four-sided closed 2D shape that has an area and a perimeter. It is also called a Trapezium. The sides of a trapezoid are parallel to each other and they are termed as the bases of the trapezoid. The non-parallel sides are known as the legs or lateral sides of a trapezoid.
Area of trapezoid :
A = ½ (a + b) h
where (A) is the area of a trapezoid, 'a' and 'b' are the bases (parallel sides), and 'h' is the height (the perpendicular distance between a and b)
According to the question
The lengths of first parallel side of a trapezoid = a
The lengths of second parallel side of a trapezoid = b
The height of a trapezoid = h
and Area of the trapezoid = \(\frac{1}{2} ah+\frac{1}{2} bh\)
Taking common
Area of the trapezoid = \(\frac{1}{2} h(a+b)\)
Hence, the area of the trapezoid as the product of two factors is \(\frac{1}{2} h(a+b)\) .
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