Answer:
The slope of BC is -7/2.
Step-by-step explanation:
Givens
ABCD is a rectangle.
AB \(\parallel\) CD
BC \(\parallel\) AD.
\(m_{AB} =\frac{2}{7}\)
We know that \(AB \perp BC\) and \(CD \perp AD\), by definition of rectangle.
Additionally, \(m_{AB} \times m_{BC}=-1\), by condition of perpendicularity.
Replacing, we have
\(\frac{2}{7} \times m_{BC}=-1\\ m_{BC}=-\frac{7}{2}\)
Therefore, the slope of BC is -7/2.
