Answered

Find all real and complex solutions by completing the square.

y^2+4y=-8

I just want someone to guide me through it please.

Verified Answer :

y^2+4y=-8
add 8 both sides
y^2+4y+8=0 in the form of ax²+bx+c=0
Factor it
by formula
-b+-(√b²-4ac)/2a
-4+-(√16-32)/2*1
-4+-(√-16)/2
-4+-4i/2
-2+-2i where√-1=i


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