add 8 both sides
x²+4x+8=0
we can't factor this
we use quadratic formula
for ax²+bx+c=0
x=\(\frac{-b+/- \sqrt{b^2-4ac} }{2a}\)
so
a=1
b=4
c=8
x=\(\frac{-4+/- \sqrt{4^2-4(1)(8)} }{2(1)}\)
x=\(\frac{-4+/- \sqrt{-16} }{2}\)
x=\(\frac{-4+/- 4i }{2}\)
x=-2+/-2i
x=-2-2i and -2+2i
A is answer
