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How many grams of HNO3 are required to prepare 500 mL of a 0.601 M HNO3 solution?

Verified Answer :

juhahah

mass of HNO3 = ?
V = 0.5L
M.mass of HNO3 = 63.0067u
Molarity = 0.601

molarity = no of moles of solute/volume of solution in L
0.601 = no of moles of solute/0.5
no of moles of solute = 0.3005

mass of HNO3 = no of moles M.mass
= 0.300563.0067
= 18.933g

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