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Which of the following is the equation of a circle whose center is at the origin and whose radius is 4?

Ax2 + y2 = 2
Bx2 + y2 = 4
Cx2 + y2 = 16

Verified Answer :

apologiabiology

(x-h)^2+(y-k)^2=r^2
center is (h,k)
radius is r

given
(0,0)=center
radius=4

(x-0)^2+(y-0)^2=4^2
x^2+y^2=16
C

Answer:

C. x^2 + y^2 = 16

Step-by-step explanation

The standard form:  (x - h)^2  +  (y-k)^2   =   r^2, where (h, k) is the center and r is the radius of the circle.

Given: (h, k) = (0, 0) and r = 4.

Now plug in the given values in the standard form, we get

(x - 0)^2 + (y - 0)^2 = 4^2

x^2 + y^2 = 16

The answer is C. x^2 + y^2 = 16

Hope this will helpful.

Thank you.

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