Answer: The given product is equal to \(6y^{-8}.\)
Step-by-step explanation: We are given to find the following product:
\(P=3y^{-4}\times 2y^{-4}.\)
We will be using the following property of exponents:
\((i)~a^x\times a^y=a^{x+y}.\)
We have
\(P\\\\=3y^{-4}\times 2y^{-4}\\\\=3\times 2\times y^{(-4)+(-4)}\\\\=6y^{-8}.\)
Therefore, the given product is equal to \(6y^{-8}.\)
