Answer : Refractive index, n = 1.57
Explanation :
It is given that,
The refractive index of a medium when the light strikes the medium after traveling through air at an angle of 23.3° and the refracted angle is 14.6°.
Incident angle, \(\angle i=23.3^0\)
Reflected angle, \(\angle r=14.6^0\)
The refractive index of a medium is given by using Snell's law :
\(n=\dfrac{sin\ i}{sin\ r}\)
\(n=\dfrac{sin(23.3)}{sin(14.6)}\)
\(n=1.57\)
So, the refractive index of the medium is 1.57
Hence, this is the required solution.
