Answer:
The probability of a homozygous dominant (BB) offspring resulting from a cross between two parents with the genotype Bb is \(25\\\)%
Explanation:
Given -
Two parents which are crossed with each other has genotype - Bb
One of their offspring has genotype BB, and this is homozygous dominant
which means B is dominant and b is recessive allele.
Lets see the punnet square of cross between the two parents with genotype "Bb"
B b
B BB Bb
b Bb bb
Four offsprings are produced out of which only one is homozygous dominant "BB"
Thus , the probability of a homozygous dominant (BB) offspring resulting from a cross between two parents with the genotype Bb is
\(\frac{1}{4} *100\\= 25%\\\)%
