Verified Answer :

ayec

let the first number be x, the second number be x+1, and the third number be x+2.

x + x+1 + x+2 = 114

3x + 3 = 114

3x = 111

x = 37

x+1 = 38

x+2 = 39

So, the three consecutive numbers are 37, 38, and 39.

apologiabiology

consecutive integers are represented by
first number=x
second=x+1
third=x+2


so x+x+1+x+2=114
solve
3x+3=114
subtract 3
3x=111
divide 3
37=x

the numbers are
37,38,39

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