jamesware32
Answered

a man is pulling on his dog with a force of 70.0 N directed at an angle of +30.0° to the horizontal. Find a the x and y components of this force

Verified Answer :

emilykay

for the horizontal (x) component: use Fx=F(cosФ)
Fx= 70N (cos 30°) = 60.6 N
for the vertical (y) component: use Fy=F(sinФ)
Fx= 70N (sin 30°) = 35.5 N

smmwaite

Answer

x-component = 35.0 N

y-component = 60.62 N


Explanation

The x-component (Fx) of 70.0 N can be found using the trigonometric ratio sine.

sin = opposite/hypotenuse

sin30 = \(\frac{Fx}{70}\)

Fx = 70 × sin30

     = 35 N

The y-component (Fy) of 70.0 N can be found using the trigonometric ratio cosine.

cos30 = \(\frac{Fy}{70}\)

Fy = 70 × cos30

      = 60.62 N

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