(2-3i)*(3+4i) perform following operations
\(\left( 2-3i \right) \left( 3+4i \right) \\ \\ =6+8i-9i-12{ i }^{ 2 }\\ \\ =6-i-12\left( -1 \right) \\ \\ =6-i+12\\ \\ =18-i\)
\((2-3i)(3+4i)=\\ 6+8i-9i+12=\\ 18-i\)
