In humans tongue rolling is dominant to the inability to tongue roll. If a heterozygous tongue roller and a non-tongue roller have a child, what are the chances the child will be a non-tongue roller? A. 0 B. 0.25 C. 0.5 D. 0.75

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lrathburn lrathburn · Answer 1 · 2015-02-21T13:08:55-05:00

In humans, tongue rolling is dominant to the inability to tongue roll. The chances a child will be a non-tongue roller is C. 0.5.

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podgorica podgorica · Answer 2 · 2019-05-21T09:24:09-04:00

Answer:

The chances of a child being non - tongue roller is \(0.5\\\)

Explanation:

Let the allele for dominant "tongue rolling trait" be represented by "T"

The allele for recessive "non-tongue rolling trait" be represented by "t"

The genotype of a heterozygous tongue rolling parent will be "Tt"

The genotype of a homozygous non- tongue rolling parent will be "tt"

If a cross is carried out between these two individuals , the offspring produced are as shown in the punnet square below-

T t

t Tt tt

So the number of offsrpings which are non- tongue roller are two in numbers represented by "tt"

So the chances that a child will be a non-tongue roller are

\(\frac{2}{4} \\= 0.5\\\)

Where , "4" represents the total number of offsprings produced