State the y-coordinate of the y-intercept for the function below f(x)=4x^(3)-12x^(2)-x+15
Note that the y-intercept is the intersection of any graph, in this case a polynomial function, and the y-axis. Furthermore, all points on the y-axis has a value of 0 for x.
Therefore, replace 0 for x and the value remaining is the y-intercept.
The answer will (0,15).
Answer:
15
Step-by-step explanation:
The given function is
\(f(x)=4x^3-12x^2-x+15\)
We need to find the y-coordinate of the y-intercept for the given function.
Substitute x=0 in the given function to find the y-intercept of the function.
\(f(0)=4(0)^3-12(0)^2-(0)+15\)
\(f(0)=4(0)-12(0)-(0)+15\)
On further simplification we get
\(f(0)=0+15\)
\(f(0)=15\)
The function intersect y-axis at (0,15).
x-coordinate of the y-intercept = 0
y-coordinate of the y-intercept = 15
Therefore the y-coordinate of the y-intercept for the given function is 15.