Prove that, if:
\(y=\frac { { x }^{ n+1 } }{ n+1 } +C\)
Then:
\(\\ \\ \frac { dy }{ dx } ={ x }^{ n }\)
By differentiating...
\(y=\frac { { x }^{ n+1 } }{ n+1 } +C\)
Then:
\(\\ \\ \frac { dy }{ dx } ={ x }^{ n }\)
By differentiating...
