How many milliliters of a stock solution of 2.00 m kno3 would you need to prepare 100ml of 1.50 m kno3?
To solve this we use the
equation,
M1V1 = M2V2
where M1 is the concentration of the stock solution, V1 is the
volume of the stock solution, M2 is the concentration of the new solution and
V2 is its volume.
2 M x V1 = 1.50 M x 100 mL
V1 = 75 mL of the 2 M KNO3 solution
75 milliliters of a stock solution of 2.00M KNO3 would you need to prepare 100ml of 1.50M KNO3.
The molarity of a solution can be calculated by using the following expression:
M1V1 = M2V2
Where;
According to this question,
2 × V1 = 100 × 1.5
2V1 = 150
V1 = 75ml
Therefore, 75 milliliters of a stock solution of 2.00M KNO3 would you need to prepare 100ml of 1.50M KNO3.
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