The equation for the circle is:
X^2 + y^2 - 12x + 6y - 19 = 0
What is the center of the circle?
A(-6, 3)
B(12, -6)
C(6, -3)
D(-12, 6)
X^2 + y^2 - 12x + 6y - 19 = 0
What is the center of the circle?
A(-6, 3)
B(12, -6)
C(6, -3)
D(-12, 6)