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Iron (fe has a density of 7.87 g/cm3 and crystallizes in a body-centered cubic structure. what is the atomic radius of iron?

Verified Answer :

Hagrid

The formula for the theoretical density of a solid crystal is
d = n M / V A
where 
d is the density
M is the molar mass
V is the volume of the cell
A is the Avogadro's number
Subsituting
7.87 = 1 (56) / (2r√2)³ (6.022x10^23)
Solve for r

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