\(\frac{n^4+18n^3+36n^2}{9n^2}\)
we can factor out a n² on top
\(\frac{n^2(n^2+18n+36)}{9n^2}\)
cancel ones (the n² on top and bottom)
\(\frac{n^2+18n+36}{9}\)
we can split the top up
remember
(a+b)/c=(a/c)+(b/c)
\(\frac{n^2+18n+36}{9}\)=
\(\frac{n^2}{9}+\frac{18n}{9}+\frac{36}{9}\)=
\(\frac{n^2}{9}+2n+4\)
that is nicest form
