We have that The the tip of a 14cm long minute hand on a clock moves \(x=14.6608 cm\) in 10 minutes,Giving the correct Answer to be \(x=14.6608 cm\)
From the question we are told that:
Length of Minute Hand \(l=14cm\)
Time \(T=10 minutes\)
Generally the angle covered in time T is mathematically given as
Since
\(60 minutes =360 \textdegree\)
Therefore
\(\theta=\frac{T}{60}*360\)
\(\theta=\frac{10}{60}*360\)
\(\theta=60 \textdegree\)
\(\theta= 1.0472 rad\)
Therefore
The distance covered by the tip of the minute hand is
\(x=\theta*r\)
Where
Length of Minute Hand l=Radius r
\(x=1.0472*14\\\\\)
\(x=14.6608 cm\)
In conclusion
The the tip of a 14cm long minute hand on a clock moves \(x=14.6608 cm\) in 10 minutes
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