Suppose C⃗ =A⃗ +B⃗ where vector A⃗ has components Ax = 5, Ay = 2 and vector B⃗ has components Bx = -3, By = -5. What is the direction of vector C⃗ ?
First, find the components of vector C (I don't know how you added the vector arrow but that's pretty cool).
Ax + Bx = Cx, Ay + By = Cy
5 + -3 = 2, 2 + -5 = -3
Vector C can be represented as 2x, -3y.
Next, using a trigonometric function tangent you may find the angle from the origin
\(\theta\) = arctan(-3/2)
\(\theta = -56.31\)° \(= -0.983\)rad
Answer:
326,3° or 146,31°
Explanation:
So you know that A=(5,2) and B=(-3,-5)
so C is going to be=(5,2)+(-3,-5)=(2,-3)
The direction of a vector is the measure of the angle it makes with a horizontal line. One of the following formulas can be used to find the direction of a vector:
tanα=\(\frac{x}{y}\)
tanα=\(\frac{2}{-3}\)---> arctg(\(\frac{2}{-3}\))=α=326,3° or 146,31°