A spinner with 10 equal-sized sections numbered 1 to 10 is spun once. What is the probability that the spinner will land on a number that is not a multiple of three?
First, we should find all the multiples of 3 from 1 to 10
31=3
32=6
3*3=9
So then we know there are 3 multiples of 3 from 1 to 10. Then there must be 7 numbers that aren't multiples of 3 (10-3=7)
Then to find probability, we do the part divided by the whole
7/10 is the final answer
Hope this helps