HELP twice a number plus twice a second number is 310. The difference between the numbers is 55. Find the numbers by writing and solving a system of equations. Explain how you solved the system. PLEASE HELP ME Thank you! I got numbers are 182.5 and 127.5 but I don't understand how to set up the system equations
Twice a number plus twice a second number is 310.
\(2x + 2y = 310\)
The difference between the numbers is 55.
\(x-y = 55\)
Divide the first equation by 2 to get a 3rd equation:
\(x+y=155\)
Add the second and third equations together:
\(x-y=55\)
\(x+y=155\)
\(2x=210\)
\(x=105\)
Put x=105 into the second equation to get:
\(105-y=55\)
\(y=50\)
So you're answers are x=105 and y=50.
The numbers by writing and solving a system of equations are 50 and 105
Let the unknown numbers be x and y
If twice a number plus twice a second number is 310, then;
2x + 2y = 310
x + y = 155
x = 155 - y
Also, If the difference of the numbers is 55, hence;
x - y = 55
155 - y - y = 55
155 - 2y = 55
-2y = 55 - 505
2y = 100
y = 50
Substitute y = 25 into 1 to have:
x = 155 - 50
x = 105
Hence the numbers by writing and solving a system of equations are 50 and 105
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