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A point is selected at random inside the given figure.



What is the probability the point will be in the region labeled D?


Enter the answer as a fraction in simplest form.

A point is selected at random inside the given figure. What is the probability the point will be in the region labeled D? Enter the answer as a fraction in simp class=

Verified Answer :

sdmatera

First we need the area of the whole shape (A=lw)
A:A=75 or 35 (7 because you add 3 and 4)
B:A=34 or 12
C:A=44 or 16
D:A=3*9 or 27 (9 because you add 5 and 4)

So the whole area is 35+12+16+27 = 90

Then we do the part divided by the whole to find probability
=27/90 which can be simplified to 3/10

Hope this helps

The probability the point will be in the region labeled D is 3/10.

What is the probability?

Probability is a measure of the likelihood of an event to occur. Many events cannot be predicted with total certainty.

The area of the whole region is;

\(\rm= (5+4)(3+4+3)\\\\=9 \times 10\\\\=90\)

The area of the region D is;

\(=3(5+4)\\\\=3\times 9\\\\=27\)

The probability the point will be in the region labeled D is;

\(\rm Probability =\dfrac{Region \ D}{Whole \ region }\\\\Probability =\dfrac{27}{90}\\\\Probability =\dfrac{3}{10}\)

Hence, the probability the point will be in the region labeled D is 3/10.

Learn more about probability here;

https://brainly.com/question/9967872

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