Factor completely 12x5 + 6x3 + 8x2.


Prime

2(6x5 + 3x3 + 4x2)

2x(6x4 + 6x2 + 4x)

2x2(6x3 + 3x + 4)

Verified Answer :

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2x²(6x³+3x+4)

Answer:

Option D is correct

factor completely of \(12x^5+6x^3+8x^2\) is\(2x^2(6x^3+3x+4)\)

Step-by-step explanation:

GCF(Greatest Common Factor) states that the largest factor that divides the polynomial.

Given the expression:

\(12x^5+6x^3+8x^2\)

By definition of GCF we have;

Factor a GCF of the given expression.

Since GCF of \(12x^5\), \(6x^3\) and \(8x^2\)  is \(2x^2\)

then;

\(2x^2(6x^3+3x+4)\)

Therefore, factor completely of \(12x^5+6x^3+8x^2\) is\(2x^2(6x^3+3x+4)\)