The rearrangement of the formula S = 2πrh + 2πr2 for h is \(h = \frac{S - 2 \pi r^2}{2 \pi r}\).
Given that,
- \(S = 2 \pi rh + 2 \pi r^2\)
- We have to arrange the above formula for h.
Based on the above information, the calculation is as follows:
\(S = 2 \pi rh + 2 \pi r^2\)
Here we have to deduct \(2 \pi r^2\) from both the sides.
Now
\(S - 2 \pi r^2 = 2 \pi rh\)
Now divide \(2 \pi r\) from both sides
So,
\(h = \frac{S - 2 \pi r^2}{2 \pi r}\)
Therefore we can conclude that the rearrangement of the formula S = 2πrh + 2πr2 for h is \(h = \frac{S - 2 \pi r^2}{2 \pi r}\).
Learn more: brainly.com/question/10726356
