Answered

A van and a truck both drove from Town A to Town B. The distance

between Town A and Town B is 200 miles. The van left Town A 1 1/2 hours

earlier than the truck. The van reached Town B 2 1/2 hours before the truck.

The truck traveled at an average speed of 40 miles per hour. What was the

average speed of the van?

Verified Answer :

First we need to find out the time it took for the truck to reach town B.

\(Speed= \frac{Distance}{Time}\)

\(40= \frac{200}{T}\)
\(T=5hours\)

Now, because the van left 1.5 hours earlier and reached the destination 2.5 hours before, it took 1 hour less the the truck to arrive.

\(5hours-1hour=4hours\) which is the time it took for the van to arrive.

Now we use the speed equation again to work out speed.

\(Speed= \frac{200}{4}\)

\(Speed=50mph\) = speed of van

Hope this helped :)

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