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MATH PLEASE HELP 12pts!


Let f(x) = 3x^2 + 2 A new quadratic function g(x) is the function f(x) stretched vertically by a factor of 4. What is the equation of g(x)?

Ag(x) = 3x^2 + 6

Bg(x) = 12x^2 + 2

Cg(x) = 3x^2 + 8

Dg(x) = 12x^2 + 8

Verified Answer :

Ag(x) = 3x^2 + 6 

If you are stretching vertically, that is along the Y axis. The original +2 is the y-intercept, so you add 4 onto the equation where the y (vertical) will be placed.

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