let's say the numbers are "a" and "b"
let's say "b" is the bigger one, and thus is 5 more than "a", or a + 5
so b = a + 5
their difference of their squares is 95, thus \(\bf b^2-a^2 =95\)
thus \(\bf \begin{cases}
b=a+5\\\\
b^2-a^2=95\\
----------\\
(a+5)^2-a^2=95
\end{cases}\)
solve for "a"
what's b? well, b = a + 5
