Enter the area of a sector with a central angle of 4π/3 radians and a radius of 12.5 cm. Use 3.14 for π and round your final answer to the nearest hundredth.
Answer:
\(327.08cm^{2}\)
Step-by-step explanation:
\(A=\frac{\pi R^{2}\alpha^{\°}}{360\°}}\); where \(\alpha^{\°}\) the central angle, and \(R\) is the radius.
\(A=\frac{\pi R^{2}\alpha^{\°}}{360\°}}= \frac{(12.5)^{2}(\frac{4\pi}{3}\pi ) }{360\°}\\A= \frac{2054.1}{6.28} =327.08cm^{2}\)
In the problem, we used \(\pi=3.14\), and \(360\°=6.28\), because the problem is asking to use radians, and we cannot operate radians with grades, it would be wrong.
Therefore, the answer is \(327.08cm^{2}\)
Answer:
327.08 cm^2
Step-by-step explanation:
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