Verified Answer :

\(\frac{ (\frac{ x^{-2} }{ y^{-3} })^2 }{ (\frac{y}{ x^{2} })^{-3} } = \frac{ (\frac{ x^{-4} }{ y^{-6} }) }{ (\frac{ y^{-3} }{ x^{-6} }) }= \frac{ x^{-4}* x^{-6} }{ y^{-3}* y^{-6} } = \frac{ x^{-10} }{ y^{-9} }\)

Panoyin

(x-²/ y-³)² = (x-²/y-³)(x-²/y-³) = (y/ x²)(y/ x²) = (y²/ x^4) = y² · x^4  =      1     
(y/ x²)-³           (y/x²)(y/x²)       (x²/y³)(x²/y³)    (x^4/ y^6)  x^4 · y^6    y^4

Related Questions