The decomposition of CCl4 is as follows:
CCl4 (g) ---> C(s) + 2Cl2 (g) Kp = 0.76
where Kp = (PCl2)^2 / (P_CCl4)
P_C is zero since carbon is in solid form.
Express P_CCl4 in terms of P_Cl2
0.76 = (P_Cl2)^2 / (P_CCl4)
0.76P_CCl4 = (P_Cl2)^2
Ptotal = P_Cl2 = 1.9 atm
Solve for P_CCl4
P_CCl4 = 4.75 atm