The length of a rectangle is 3 inches more than its width. The perimeter of the rectangle is 34 inches. The length of the rectangle is inches, and its width is inches.
l=3+w
w=w
p=2(3+w)+2w
p=6+2w+2w
p=6+4w
34=6+4w
28=4w
w=7
l=10
Answer:
The width of rectangle is 7 inches.
The length of rectangle is 10 inches.
Step-by-step explanation:
Let w represent width and l represent length of the rectangle.
We have been given that the length of a rectangle is 3 inches more than its width. We can represent this information in an equation as:
\(l=w+3...(1)\)
We are also told that the perimeter of the rectangle is 34 inches. We know that perimeter of a rectangle is two times its width and length. We can represent this information in an equation as:
\(2(w+l)=34...(2)\)
Upon substituting equation (1) in equation (2), we will get:
\(2(w+w+3)=34\)
\(2(2w+3)=34\)
Using distributive property \(a(b+c)=ab+ac\), we will get:
\(2*2w+2*3=34\)
\(4w+6=34\)
\(4w+6-6=34-6\)
\(4w=28\)
\(\frac{4w}{4}=\frac{28}{4}\)
\(w=7\)
Therefore, the width of rectangle is 7 inches.
Upon substituting \(w=7\) in equation (1), we will get:
\(l=w+3\)
\(l=7+3\)
\(l=10\)
Therefore, the length of rectangle is 10 inches.