amyfullmer
Answered

Find the number of real number solutions for the equation.

X^2-10x+25=0


A: 2

B: Cannot be determined

C: 0

D: 1

Verified Answer :

Determinant = b² - 4ac = (-10)² + 4125 = 100 - 100 = 0

So it has 1 solution.
Answer is D

ghanami

Hello here is a solution :
x²-10x+25 = 0
x² -2(x)(5)+5² =0
puy identity  : a²-2ab+b² = (a-b)²
(x-5)² = 0
x-5 = 0
the solution is : 5

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