To find where there are holes, we need to make the function = \(\frac{0}{0}\).
\(\frac{(x-5)(x-2)}{(x-2)(x+4)}\)
If you plug in \(x=2\), you get \(\frac{0}{0}\), which means there is a hole in the graph when \(x=2\)
To find where there are vertical asymptotes, we need to make just the bottom 0.
Ex. \(\frac{1}{0}\)
\(\frac{(x-5)(x-2)}{(x-2)(x+4)}\)
If you plug in \(x=-4\), you get \(\frac{(-9)(-6)}{0} = \frac{54}{0}\), which means there is a vertical asymptote when \(x=-4\)
