bilalmahmoud bilalmahmoud

08-03-2017
Mathematics

Answered

A ball is shot straight up into the air from the ground with initial velocity of 45ft/sec. Assuming that the air resistance can be ignored, how high does it go?

Verified Answer :

aksareji6 aksareji6

08-03-2017

V2^2 = V1^2 - 2gh

=> 0 = 44^2 - 2 (32.2) h

=> h = 44^2 / 64.4 = 30.062 ft

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