Data:
\(P_{1} = 3.4\:atm\)
\(T_{1} = 713\:K\)
\(P_{2} = ?\)
\(T_{2} = 273\:K\)
Formula:
\(\frac{ P_{1} }{ T_{1} } = \frac{ P_{2} }{ T_{2} }\)
Product of extremes equals product of means
\(P_{1} * T_{2} = P_{2} * T_{1}\)
Solving:
\(P_{1} * T_{2} = P_{2} * T_{1}\)
\(3.4*713 = P_{2} * 273\)
\(2424.2 = 273P_{2}\)
\(273P_{2} = 2424.2\)
\(P_{2} = \frac{2424.2}{273}\)
\(\boxed{\boxed{P_{2} \approx 8.87\:atm}}\end{array}}\qquad\quad\checkmark\)
