if f(x)=4x^2-3 and g(x)=x+1,find (f-g)(x)
A.4x^2-x-2
B.4x^3-3
C.x-4x^2-2
D.4x^2-x-4

Verified Answer :

Hello here is a solution :

(f-g)(x) =f(x) - g(x) 
            = (4x²-3)-(x+1)
            = 4x² -x -4   ( answer :D)

Answer:

Option D is correct

The value of \((f-g)(x)\) is, \(4x^2-x-4\)

Step-by-step explanation:

Given the function:

\(f(x) = 4x^2-3\)

\(g(x) = x+1\)

We have to find \((f-g)(x)\)

\((f-g)(x) = f(x)-g(x)\)

Substitute the given functions we have;

\((f-g)(x) = 4x^2-3-x-1\)

⇒\((f-g)(x)=4x^2-x-4\)

Therefore, the value of \((f-g)(x)\) is, \(4x^2-x-4\)