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23 grams of sodium reacted with 35.5g of chlorine. Calculate the mass of the sodium chloride compound formed.


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Verified Answer :

xxkkxx2029


NaOH + HCl --> NaCl + H2Oso here 1 mole of NaOH reacts with 1 mole of HCl. Hence it is required to convert the amount of HCl and NaOH in to moles.Number of HCl moles Concentration of the solution = 2.00M = 2 mol/ literVolume of the solution           = 22.4 mlNumber of HCl moles              = (2mol/1000 ml)*22.4 ml                                            =  0.0448 mol

raspberry123

NaOH + HCl --> NaCl + H2Oso here 1 mole of NaOH reacts with 1 mole of HCl. Hence it is required to convert the amount of HCl and NaOH in to moles.Number of HCl moles Concentration of the solution = 2.00M = 2 mol/ literVolume of the solution           = 22.4 mlNumber of HCl moles              = (2mol/1000 ml)*22.4 ml                                            =  0.0448 mol