The elastic potential energy (Ep) is given by \(Ep = \frac{1}{2}*k*x^2\)
Data:
Ep = 5184 J
k = 16200 N/m
x (displacement) = ?
Solving:
\(Ep = \frac{1}{2}*k*x^2\)
\(5184 = \frac{1}{2}*16200*x^2\)
\(5184*2 = 16200x^2\)
\(10368 = 16200x^2\)
\(16200x^2 = 10368\)
\(x^2 = \frac{10638}{16200}\)
\(x^2 = 0.64\)
\(x = \sqrt{0.64}\)
\(\boxed{\boxed{x = 0.8\:m}}\end{array}}\qquad\quad\checkmark\)
