a photon has a wavelength of 624 nm. calculate the energy of the photon in joules
624 nm x 10^-9 = 6.2 x 10^-7
(3.00 x 10^8) divided by (6.2 x 10^-7) = 4.8 x 10^14
(6.63 x 10^-34 J) x ( 4.8 x 10^14) = 3.2 x 10^-9 Joules
Answer: The energy of the photon is \(3.185\times 10^{-19}J\)
Explanation:
To calculate the energy of the photon, we use the equation given by Planck which is:
\(\Delta E=\frac{hc}{\lambda}\)
where,
\(\lambda\) = Wavelength of the photon = \(624nm=6.24\times 10^{-7}m\) (Conversion factor: \(1m=10^9nm\) )
h = Planck's constant = \(6.624\times 10^{-34}Js\)
c = speed of light = \(3\times 10^8m/s\)
\(\Delta E\) = energy of the photon
Putting values in above equation, we get:
\(E=\frac{6.624\times 10^{-34}\times 3\times 10^8}{6.24\times 10^{-7}}\\\\E=3.185\times 10^{-19}J\)
Hence, the energy of the complex is \(3.185\times 10^{-19}J\)