How many moles of water are produced when 3.25 moles of co2 are formed during the combustion of methyl alcohol (ch3oh)? 2ch3oh 3o2 → 2co2 4h2o 1.62 moles 3.25 moles 6.50 moles 13.00 moles

Verified Answer :

2CH₃OH  +  3O₂  →  2CO₂ +  4H₂O

mole ratio of CO₂  :  H₂O  is  2  :  4 (simplified as 1 : 2)

∴ if moles of CO₂ = 3.25 moles

then moles of H₂O = 3.25 moles × 2
             
                              = 6.50 moles

Answer : The number of moles of water produced are, 6.50 moles

Explanation : Given,

Moles of carbon dioxide \((CO_2)\) = 3.25 mole

The given balanced chemical reaction is :

\(2CH_3OH+3O_2\rightarrow 2CO_2+4H_2O\)

From the given balanced chemical reaction, we conclude that 2 moles of methyl alcohol react with 3 moles of oxygen to produced 2 moles of carbon dioxide and 4 moles of water.

When 2 moles of carbon dioxide is produced then 4 moles of water is also produced

Now, when 3.25 moles of carbon dioxide is produced then \(\frac{4}{2}\times 3.25=6.50moles\) of water is also produced

Therefore, the number of moles of water produced are, 6.50 moles