How many moles of water are produced when 3.25 moles of co2 are formed during the combustion of methyl alcohol (ch3oh)? 2ch3oh 3o2 → 2co2 4h2o 1.62 moles 3.25 moles 6.50 moles 13.00 moles
2CH₃OH + 3O₂ → 2CO₂ + 4H₂O
mole ratio of CO₂ : H₂O is 2 : 4 (simplified as 1 : 2)
∴ if moles of CO₂ = 3.25 moles
then moles of H₂O = 3.25 moles × 2
= 6.50 moles
Answer : The number of moles of water produced are, 6.50 moles
Explanation : Given,
Moles of carbon dioxide \((CO_2)\) = 3.25 mole
The given balanced chemical reaction is :
\(2CH_3OH+3O_2\rightarrow 2CO_2+4H_2O\)
From the given balanced chemical reaction, we conclude that 2 moles of methyl alcohol react with 3 moles of oxygen to produced 2 moles of carbon dioxide and 4 moles of water.
When 2 moles of carbon dioxide is produced then 4 moles of water is also produced
Now, when 3.25 moles of carbon dioxide is produced then \(\frac{4}{2}\times 3.25=6.50moles\) of water is also produced
Therefore, the number of moles of water produced are, 6.50 moles