Sketch the following to help answer the question. Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P. Side QR = 5m and diagonal QS = 6m. Find the length of segment RP.
Adjacent sides of kite are equal and diagonal intersects at 90 so it will bisect the other diagonal
according to pythagorean theorm
hy^2=l^2+b^2
5^2-3^2=b^2
25=9=b^2
b=4
RP=4 m
Answer:
Step-by-step explanation:
Given: Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P. Side QR = 5m and diagonal QS = 6m.
Since, diagonals of kite bisect each other, thus QP=6m
Now, in ΔPQR, we have
\((QR)^{2}=(RP)^{2}+(QP)^{2}\)
\((5)^{2}=(3)^2+(RP)^2\)
\(25=9+(RP)^2\)
\(25-9=(RP)^2\)\(16=(RP)^2\)
\(RP=4m\)
Therefore, the length of segment RP is 4m.