Answer:
Applying factor polynomials, you will find:
\(3a^2+5a-12=\left(3a-4\right)\left(a+3\right)\)
Step-by-step explanation:
The exercise presents the equation: \(3a^{2} + 5a - 12\).
For factoring an equation, you should write the given equation in factors. Therefore, for solving this exercise, you need to find the factors.
- You should rewrite the equation.
\(3a^2+5a-12= 3a^2-4a+5a-12\)
2. After that, you should break the expression in groups.
\(3a^2-4a+5a-12= (3a^2-4a)+(9a-12)\)
3. Next step, you should factor out each term. For the first factor use a and the second factor use 3.
\((3a^2-4a)+(9a-12)= a(3a-4)+3(3a-4)\)
Here it is possible to see that \((3a-4)\) is a factor common.
4. Finally, factor out \(\left(3a-4\right)\\) in previous expression.
\(\left(3a-4\right)\left(a+3\right)\)
Thus, \(3a^2+5a-12=\left(3a-4\right)\left(a+3\right)\).
Learn more about factor an expression here:
https://brainly.com/question/11579257
