According to the VSEPR theory, what is the shape of a molecule that has a central atom bound to three other atoms with no lone pairs of electrons?

Atetrahedral
Bbent
Clinear
Dtrigonal bipyramidal
Etrigonal planar

Verified Answer :

E.) The shape of molecule which can form 3 bonds and no lone pair of electrons on central atom is trigonal planar.

Answer: E. trigonal planar

Explanation:  

According to VSEPR theory:

\(:{\text{Number of electrons}} =\frac{1}{2}[V+N-C+A]\)

where, V = number of valence electrons present in central atom i.e. carbon = 4

N = number of monovalent atoms bonded to central atom=3

C = charge of cation = 0

A = charge of anion = -1

If a central atom is bound to three other atoms with no lone pairs of electrons,the number of electrons is 3 that means the hybridization will be \(sp^2\) and the electronic geometry of the molecule will be trigonal planar as the electron pairs will repel each other and attain a position which is most stable.


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