A group of kangaroo friends had a jumping contest and measured their jumps. pocket jumped 16 meters, hopster jumped 9 meters, and joey jumped 5 meters.find the mean length.
Answer:
Mean of the lengths = 10 meters
Step-by-step explanation:
A group for kangaroo friends had a jumping contest and measured their jumps.
Pocket jumped 16 meters. hopster jumped 9 meters and joey jumped 5 meters.
We have to calculate the mean length of their jumps.
Since mean of jumps will be = \(\frac{\text{Total lengths of jumps}}{\text{number of kangaroo friends}}\)
Mean = \(\frac{(16+9+5)}{3}\)
= \(\frac{30}{3}\)
= 10 meters
The mean length of the three is 10 meters.
The mean is the average of all the observations of a set of numbers. it is found by dividing the sum of all the observations of the set by the number of observations in the set.
\(\rm{Mean=\dfrac{Sum\ of\ observations}{Number\ of\ observations}\)
Given to us
We know that the mean is the average, therefore,
Sum of all the observations = 16 + 9 + 5 = 30
Number of observations = 3
\(\rm{Mean=\dfrac{Sum\ of\ observations}{Number\ of\ observations}\)
\(\rm{Mean=\dfrac{30}{3} = 10\)
Hence, the mean length of the three is 10 meters.
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