Sailee
Answered

Locate the foci of ellipse. Show your work.

X^2/36 +y^2/11 =1

Verified Answer :

In this equation, 36>11 and so the ellipse has major axis along x axis

standard equation of ellipse with major axis is along x axis

x^2/a^2+y^2/b^2=1,

the foci are at (ae,0) and (–ae,0)

eccentricity e is given by

ae=√(a^2-b^2)


In this case ae=√(36-11)= √25=+/- 5


Focii are(-5,0) and(5,0)